What is the answer to 2^{x^2+7x}=8^{-4} ?

The answer to 2^{x^2+7x}=8^{-4} is x=-3,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x^2+7x}=8^{-4}

2^{x^{2} + 7 x} = 8^{- 4}

x = - 3, x = - 4

Solution steps

2^{x^{2} + 7 x} = 8^{- 4}

Apply exponent rules

x^{2} + 7 x = - 12

Solve

x^{2} + 7 x = - 12 : x = - 3, x = - 4

x = - 3, x = - 4

x, 2 = e^{x y}

x, ln (e^{x} - 3) = 2

2^{x^{2} - 4 x - 12} = 8^{x + 2}

12 1^{2 x} = 1 1^{x + 3}

x, 3^{3 x - 2} = 9^{x}

What is the answer to 2^{x^2+7x}=8^{-4} ?
The answer to 2^{x^2+7x}=8^{-4} is x=-3,x=-4
Solve for x: 2^{x^2+7x}=8^{-4}
The solution is x=-3,x=-4