What is the answer to 7^{3x+2}=28 ?

The answer to 7^{3x+2}=28 is x=(ln(4/7))/(3ln(7))

Solve for x: 7^{3x+2}=28

The solution is x=(ln(4/7))/(3ln(7))

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7^{3 x + 2} = 28

x = \frac{ln ( \frac{4}{7} )}{3 ln ( 7 )}

Decimal Notation

x = - 0.09586 \dots

Solution steps

7^{3 x + 2} = 28

Apply exponent rules

(3 x + 2) ln (7) = ln (28)

Solve

(3 x + 2) ln (7) = ln (28) : x = \frac{ln ( \frac{4}{7} )}{3 ln ( 7 )}

x = \frac{ln ( \frac{4}{7} )}{3 ln ( 7 )}

7^{3 x + 2} = 35

3^{2 x + 1} + 3^{x + 2} = 12

5^{x + 1} + 5^{1 - x} = 11

- 7 \cdot 3^{0.25 x} = - 10

2^{- x} \cdot 2^{3 x} = 64

What is the answer to 7^{3x+2}=28 ?
The answer to 7^{3x+2}=28 is x=(ln(4/7))/(3ln(7))
Solve for x: 7^{3x+2}=28
The solution is x=(ln(4/7))/(3ln(7))