What is the answer to 7^{3x+2}=35 ?

The answer to 7^{3x+2}=35 is x=(ln(5/7))/(3ln(7))

Solve for x: 7^{3x+2}=35

The solution is x=(ln(5/7))/(3ln(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7^{3 x + 2} = 35

x = \frac{ln ( \frac{5}{7} )}{3 ln ( 7 )}

Decimal Notation

x = - 0.05763 \dots

Solution steps

7^{3 x + 2} = 35

Apply exponent rules

(3 x + 2) ln (7) = ln (35)

Solve

(3 x + 2) ln (7) = ln (35) : x = \frac{ln ( \frac{5}{7} )}{3 ln ( 7 )}

x = \frac{ln ( \frac{5}{7} )}{3 ln ( 7 )}

3^{2 x + 1} + 3^{x + 2} = 12

5^{x + 1} + 5^{1 - x} = 11

- 7 \cdot 3^{0.25 x} = - 10

2^{- x} \cdot 2^{3 x} = 64

9^{3 p} = 2 7^{1 - 3 p}

What is the answer to 7^{3x+2}=35 ?
The answer to 7^{3x+2}=35 is x=(ln(5/7))/(3ln(7))
Solve for x: 7^{3x+2}=35
The solution is x=(ln(5/7))/(3ln(7))