What is the answer to 2(10)^x+10^{x+1}=4 ?

The answer to 2(10)^x+10^{x+1}=4 is x=-(ln(3))/(ln(10))

Solve for x: 2(10)^x+10^{x+1}=4

The solution is x=-(ln(3))/(ln(10))

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2 (10)^{x} + 1 0^{x + 1} = 4

x = - \frac{ln ( 3 )}{ln ( 10 )}

Decimal Notation

x = - 0.47712 \dots

Solution steps

2 (10)^{x} + 1 0^{x + 1} = 4

Factor

2 \cdot 1 0^{x} + 1 0^{x + 1} : 3 \cdot 5^{x} \cdot 2^{2 + x}

3 \cdot 5^{x} \cdot 2^{2 + x} = 4

Apply exponent rules

x ln (10) = ln (\frac{1}{3})

Solve

x ln (10) = ln (\frac{1}{3}) : x = - \frac{ln ( 3 )}{ln ( 10 )}

x = - \frac{ln ( 3 )}{ln ( 10 )}

67 = 2 1^{x}

y = b + a e^{- x}, x

x, e^{x^{2} + 1} = 5 e^{- x}

4^{3 x - 15} - 64 = 0

2^{x^{2}} = 8

What is the answer to 2(10)^x+10^{x+1}=4 ?
The answer to 2(10)^x+10^{x+1}=4 is x=-(ln(3))/(ln(10))
Solve for x: 2(10)^x+10^{x+1}=4
The solution is x=-(ln(3))/(ln(10))