What is the answer to (sqrt(2))^{3x-1}=32 ?

The answer to (sqrt(2))^{3x-1}=32 is x= 11/3

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(sqrt(2))^{3x-1}=32

(2)^{3 x - 1} = 32

x = \frac{11}{3}

Decimal Notation

x = 3.66666 \dots

Solution steps

(2)^{3 x - 1} = 32

Apply exponent rules

\frac{1}{2} (3 x - 1) = 5

Solve

\frac{1}{2} (3 x - 1) = 5 : x = \frac{11}{3}

x = \frac{11}{3}

3^{(x^{2} + 4 x)} = \frac{1}{27}

4^{2 x - 1} = 5^{x + 2}

e^{(2 x)} - 2 e^{(x)} - 24 = 0

25 6^{- 1} = 1 6^{2 x - 2}

x, 2^{x} 3^{y} = 6

What is the answer to (sqrt(2))^{3x-1}=32 ?
The answer to (sqrt(2))^{3x-1}=32 is x= 11/3
Solve for x: (sqrt(2))^{3x-1}=32
The solution is x= 11/3