What is the answer to 3^{x-3}=17^{-5x} ?

The answer to 3^{x-3}=17^{-5x} is x=(3ln(3))/(ln(3)+5ln(17))

Solve for x: 3^{x-3}=17^{-5x}

The solution is x=(3ln(3))/(ln(3)+5ln(17))

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3^{x - 3} = 1 7^{- 5 x}

x = \frac{3 ln ( 3 )}{ln ( 3 ) + 5 ln ( 17 )}

Decimal Notation

x = 0.21591 \dots

Solution steps

3^{x - 3} = 1 7^{- 5 x}

Apply exponent rules

(x - 3) ln (3) = - 5 x ln (17)

Solve

(x - 3) ln (3) = - 5 x ln (17) : x = \frac{3 ln ( 3 )}{ln ( 3 ) + 5 ln ( 17 )}

x = \frac{3 ln ( 3 )}{ln ( 3 ) + 5 ln ( 17 )}

9 e^{x} = 3

2^{2 x - 1} = 5^{x + 5}

x, 13 (1 + e^{- x})^{- 1} = 2

3 6^{2 m} = 21 6^{m - 3}

p, b^{p} b^{5} = b^{9}

What is the answer to 3^{x-3}=17^{-5x} ?
The answer to 3^{x-3}=17^{-5x} is x=(3ln(3))/(ln(3)+5ln(17))
Solve for x: 3^{x-3}=17^{-5x}
The solution is x=(3ln(3))/(ln(3)+5ln(17))