What is the answer to solvefor x,13(1+e^{-x})^{-1}=2 ?

The answer to solvefor x,13(1+e^{-x})^{-1}=2 is x=-ln(11/2)

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solvefor x,13(1+e^{-x})^{-1}=2

solve for

x, 13 (1 + e^{- x})^{- 1} = 2

x = - ln (\frac{11}{2})

Decimal Notation

x = - 1.70474 \dots

Solution steps

13 (1 + e^{- x})^{- 1} = 2

Rewrite the equation with

e^{- x} = u

13 (1 + u)^{- 1} = 2

Solve

13 (1 + u)^{- 1} = 2 : u = \frac{11}{2}

u = \frac{11}{2}

Substitute back

u = e^{- x},

solve for

x

Solve

e^{- x} = \frac{11}{2} : x = - ln (\frac{11}{2})

x = - ln (\frac{11}{2})

3 6^{2 m} = 21 6^{m - 3}

p, b^{p} b^{5} = b^{9}

8^{x} = (2)^{2 x^{2} + 4}

x, y^{1} = e^{x}

20 \cdot 2^{x} = 5 \cdot 3^{x}

What is the answer to solvefor x,13(1+e^{-x})^{-1}=2 ?
The answer to solvefor x,13(1+e^{-x})^{-1}=2 is x=-ln(11/2)