What is the answer to 2^{2x-1}=5^{x+5} ?

The answer to 2^{2x-1}=5^{x+5} is x=(ln(6250))/(2ln(2)-ln(5))

Solve for x: 2^{2x-1}=5^{x+5}

The solution is x=(ln(6250))/(2ln(2)-ln(5))

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2^{2 x - 1} = 5^{x + 5}

x = \frac{ln ( 6250 )}{2 ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = - 39.16912 \dots

Solution steps

2^{2 x - 1} = 5^{x + 5}

Apply exponent rules

(2 x - 1) ln (2) = (x + 5) ln (5)

Solve

(2 x - 1) ln (2) = (x + 5) ln (5) : x = \frac{ln ( 6250 )}{2 ln ( 2 ) - ln ( 5 )}

x = \frac{ln ( 6250 )}{2 ln ( 2 ) - ln ( 5 )}

x, 13 (1 + e^{- x})^{- 1} = 2

3 6^{2 m} = 21 6^{m - 3}

p, b^{p} b^{5} = b^{9}

8^{x} = (2)^{2 x^{2} + 4}

x, y^{1} = e^{x}

What is the answer to 2^{2x-1}=5^{x+5} ?
The answer to 2^{2x-1}=5^{x+5} is x=(ln(6250))/(2ln(2)-ln(5))
Solve for x: 2^{2x-1}=5^{x+5}
The solution is x=(ln(6250))/(2ln(2)-ln(5))