What is the answer to solvefor x,5^{2y}=3^{2x+1} ?

The answer to solvefor x,5^{2y}=3^{2x+1} is x=(2ln(5)y-ln(3))/(2ln(3))

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solvefor x,5^{2y}=3^{2x+1}

solve for

x, 5^{2 y} = 3^{2 x + 1}

x = \frac{2 ln ( 5 ) y - ln ( 3 )}{2 ln ( 3 )}

Solution steps

5^{2 y} = 3^{2 x + 1}

Apply exponent rules

2 y ln (5) = (2 x + 1) ln (3)

Solve

2 y ln (5) = (2 x + 1) ln (3) : x = \frac{2 ln ( 5 ) y - ln ( 3 )}{2 ln ( 3 )}

x = \frac{2 ln ( 5 ) y - ln ( 3 )}{2 ln ( 3 )}

9^{x + 4} = 2 7^{5 x - 2}

3 e^{5 x} = 8943

2^{2 x} \cdot 2 = 3^{x} \cdot 3^{3}

7^{2 x} = 7^{x - 3}

1000000 = 27000 \cdot 131 2^{x}

What is the answer to solvefor x,5^{2y}=3^{2x+1} ?
The answer to solvefor x,5^{2y}=3^{2x+1} is x=(2ln(5)y-ln(3))/(2ln(3))