What is the answer to (3^x)*4^{(x+2)}=8 ?

The answer to (3^x)*4^{(x+2)}=8 is x=-(ln(2))/(ln(12))

Solve for x: (3^x)*4^{(x+2)}=8

The solution is x=-(ln(2))/(ln(12))

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(3^{x}) \cdot 4^{(x + 2)} = 8

x = - \frac{ln ( 2 )}{ln ( 12 )}

Decimal Notation

x = - 0.27894 \dots

Solution steps

(3^{x}) \cdot 4^{(x + 2)} = 8

Apply exponent rules

x ln (12) = ln (\frac{1}{2})

Solve

x ln (12) = ln (\frac{1}{2}) : x = - \frac{ln ( 2 )}{ln ( 12 )}

x = - \frac{ln ( 2 )}{ln ( 12 )}

2 7^{3 x} = 9^{x + 2}

2 = x + e^{x}

2^{x} = \frac{2}{2}

17 = 2^{n}

1 0^{5} = (1 0^{- 13}) (1 0^{x})

What is the answer to (3^x)*4^{(x+2)}=8 ?
The answer to (3^x)*4^{(x+2)}=8 is x=-(ln(2))/(ln(12))
Solve for x: (3^x)*4^{(x+2)}=8
The solution is x=-(ln(2))/(ln(12))