What is the answer to 4(3)^x=7(5)^x ?

The answer to 4(3)^x=7(5)^x is x=(ln(7)-2ln(2))/(ln(3)-ln(5))

Solve for x: 4(3)^x=7(5)^x

The solution is x=(ln(7)-2ln(2))/(ln(3)-ln(5))

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4 (3)^{x} = 7 (5)^{x}

x = \frac{ln ( 7 ) - 2 ln ( 2 )}{ln ( 3 ) - ln ( 5 )}

Decimal Notation

x = - 1.09551 \dots

Solution steps

4 (3)^{x} = 7 (5)^{x}

Apply exponent rules

ln (4) + x ln (3) = ln (7) + x ln (5)

Solve

ln (4) + x ln (3) = ln (7) + x ln (5) : x = \frac{ln ( 7 ) - 2 ln ( 2 )}{ln ( 3 ) - ln ( 5 )}

x = \frac{ln ( 7 ) - 2 ln ( 2 )}{ln ( 3 ) - ln ( 5 )}

2 e^{2 x} + e^{x} - 6 = 0

8^{2 + x^{2}} = 1 0^{2}

7^{x + 4} = 3

lo g_{27} (3^{x + 2}) = - 2

2^{2 x} - 6 \cdot 2^{x + 1} + 32 = 0

What is the answer to 4(3)^x=7(5)^x ?
The answer to 4(3)^x=7(5)^x is x=(ln(7)-2ln(2))/(ln(3)-ln(5))
Solve for x: 4(3)^x=7(5)^x
The solution is x=(ln(7)-2ln(2))/(ln(3)-ln(5))