What is the answer to 2^{x+1}=3^{2x-5} ?

The answer to 2^{x+1}=3^{2x-5} is x=(ln(486))/(2ln(3)-ln(2))

Solve for x: 2^{x+1}=3^{2x-5}

The solution is x=(ln(486))/(2ln(3)-ln(2))

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2^{x + 1} = 3^{2 x - 5}

x = \frac{ln ( 486 )}{2 ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 4.11295 \dots

Solution steps

2^{x + 1} = 3^{2 x - 5}

Apply exponent rules

(x + 1) ln (2) = (2 x - 5) ln (3)

Solve

(x + 1) ln (2) = (2 x - 5) ln (3) : x = \frac{ln ( 486 )}{2 ln ( 3 ) - ln ( 2 )}

x = \frac{ln ( 486 )}{2 ln ( 3 ) - ln ( 2 )}

4000000 = 500000 \cdot 1. 1^{t}

2^{2 x} - 12 \cdot 2^{x} = - 32

e^{e x} = 10

4 = \frac{e ^{2 + x}}{1 - e ^{2 + x}}

\frac{2 ^{- x^{2} + 3 x}}{2} = 2

What is the answer to 2^{x+1}=3^{2x-5} ?
The answer to 2^{x+1}=3^{2x-5} is x=(ln(486))/(2ln(3)-ln(2))
Solve for x: 2^{x+1}=3^{2x-5}
The solution is x=(ln(486))/(2ln(3)-ln(2))