What is the answer to 2^{X-1}-2^X+2^{X+1}=48 ?

The answer to 2^{X-1}-2^X+2^{X+1}=48 is X=5

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2^{X-1}-2^X+2^{X+1}=48

2^{X - 1} - 2^{X} + 2^{X + 1} = 48

X = 5

Solution steps

2^{X - 1} - 2^{X} + 2^{X + 1} = 48

Factor

2^{X - 1} - 2^{X} + 2^{X + 1} : 3 \cdot 2^{X - 1}

3 \cdot 2^{X - 1} = 48

Divide both sides by

3

2^{X - 1} = 16

Apply exponent rules

X - 1 = 4

Solve

X - 1 = 4 : X = 5

X = 5

2 (2^{3 x - 1}) = 8

9^{x - 1} = 3 6^{x}

90 e^{0.32 x} = 184.3613

lo g_{3} (3^{x}) = - 1

5^{2 x - 1} = 8^{x}

What is the answer to 2^{X-1}-2^X+2^{X+1}=48 ?
The answer to 2^{X-1}-2^X+2^{X+1}=48 is X=5
Solve for X: 2^{X-1}-2^X+2^{X+1}=48
The solution is X=5