What is the answer to (2^{-x^2+3x})/2 =2 ?

The answer to (2^{-x^2+3x})/2 =2 is x=1,x=2

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(2^{-x^2+3x})/2 =2

\frac{2 ^{- x^{2} + 3 x}}{2} = 2

x = 1, x = 2

Solution steps

\frac{2 ^{- x^{2} + 3 x}}{2} = 2

Apply exponent rules

- x^{2} + 3 x - 1 = 1

Solve

- x^{2} + 3 x - 1 = 1 : x = 1, x = 2

x = 1, x = 2

2^{X - 1} - 2^{X} + 2^{X + 1} = 48

2 (2^{3 x - 1}) = 8

9^{x - 1} = 3 6^{x}

90 e^{0.32 x} = 184.3613

lo g_{3} (3^{x}) = - 1

What is the answer to (2^{-x^2+3x})/2 =2 ?
The answer to (2^{-x^2+3x})/2 =2 is x=1,x=2
Solve for x: (2^{-x^2+3x})/2 =2
The solution is x=1,x=2