What is the answer to 9^{x+1}=27^{4x-2} ?

The answer to 9^{x+1}=27^{4x-2} is x= 4/5

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9^{x+1}=27^{4x-2}

9^{x + 1} = 2 7^{4 x - 2}

x = \frac{4}{5}

Decimal Notation

x = 0.8

Solution steps

9^{x + 1} = 2 7^{4 x - 2}

Apply exponent rules

2 (x + 1) = 3 (4 x - 2)

Solve

2 (x + 1) = 3 (4 x - 2) : x = \frac{4}{5}

x = \frac{4}{5}

e^{e^{x}} = 14

7^{x + 4} = π^{2 x}

5^{3 x + 1} = 5^{3 x + 2} - 100

x, - f = 2^{x} + 1

2^{x} + 2^{x + 2} = \frac{9}{2}

What is the answer to 9^{x+1}=27^{4x-2} ?
The answer to 9^{x+1}=27^{4x-2} is x= 4/5
Solve for x: 9^{x+1}=27^{4x-2}
The solution is x= 4/5