What is the answer to 6^{x+3}=17 ?

The answer to 6^{x+3}=17 is x=(ln(17))/(ln(6))-3

Solve for x: 6^{x+3}=17

The solution is x=(ln(17))/(ln(6))-3

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6^{x + 3} = 17

x = \frac{ln ( 17 )}{ln ( 6 )} - 3

Decimal Notation

x = - 1.41875 \dots

Solution steps

6^{x + 3} = 17

Apply exponent rules

(x + 3) ln (6) = ln (17)

Solve

(x + 3) ln (6) = ln (17) : x = \frac{ln ( 17 )}{ln ( 6 )} - 3

x = \frac{ln ( 17 )}{ln ( 6 )} - 3

1 0^{x - 3} = 2^{10 + x}

6^{x + 3} = 36

3^{2 x} = 2 7^{4}

2^{2 x - 1} = 3^{x}

x, 4^{2 x} = 8^{x} (2)

What is the answer to 6^{x+3}=17 ?
The answer to 6^{x+3}=17 is x=(ln(17))/(ln(6))-3
Solve for x: 6^{x+3}=17
The solution is x=(ln(17))/(ln(6))-3