What is the answer to 5^{2x}=6^{x+1} ?

The answer to 5^{2x}=6^{x+1} is x=(ln(6))/(2ln(5)-ln(6))

Solve for x: 5^{2x}=6^{x+1}

The solution is x=(ln(6))/(2ln(5)-ln(6))

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5^{2 x} = 6^{x + 1}

x = \frac{ln ( 6 )}{2 ln ( 5 ) - ln ( 6 )}

Decimal Notation

x = 1.25551 \dots

Solution steps

5^{2 x} = 6^{x + 1}

Apply exponent rules

2 x ln (5) = (x + 1) ln (6)

Solve

2 x ln (5) = (x + 1) ln (6) : x = \frac{ln ( 6 )}{2 ln ( 5 ) - ln ( 6 )}

x = \frac{ln ( 6 )}{2 ln ( 5 ) - ln ( 6 )}

2^{x + 1} = 1 6^{x - 4}

\frac{6 e ^{x}}{( 6 + e ^{x} ) ^{2}} = 0

4^{x + 1} = 3

1 2^{x - 2} = 20

4 9^{x} - 8 \cdot 7^{x} + 7 = 0

What is the answer to 5^{2x}=6^{x+1} ?
The answer to 5^{2x}=6^{x+1} is x=(ln(6))/(2ln(5)-ln(6))
Solve for x: 5^{2x}=6^{x+1}
The solution is x=(ln(6))/(2ln(5)-ln(6))