What is the answer to 4^{x+0.5}-17*2^x+8=0 ?

The answer to 4^{x+0.5}-17*2^x+8=0 is x=3,x=-1

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4^{x+0.5}-17*2^x+8=0

4^{x + 0.5} - 17 \cdot 2^{x} + 8 = 0

x = 3, x = - 1

Solution steps

4^{x + 0.5} - 17 \cdot 2^{x} + 8 = 0

Apply exponent rules

(2^{x})^{2} \cdot 2^{1} - 17 \cdot 2^{x} + 8 = 0

Rewrite the equation with

2^{x} = u

(u)^{2} \cdot 2^{1} - 17 u + 8 = 0

Solve

u^{2} \cdot 2^{1} - 17 u + 8 = 0 : u = 8, u = \frac{1}{2}

u = 8, u = \frac{1}{2}

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 8 : x = 3

Solve

2^{x} = \frac{1}{2} : x = - 1

x = 3, x = - 1

4 e^{- x - 1} = 12

4^{x + 3} = 1 6^{x^{2} - 2 x}

12 8^{x} = 4 \cdot 2^{x}

e^{2 x} = e^{x^{2} - 8}

y, e^{- x^{2} - y^{2}} = c

What is the answer to 4^{x+0.5}-17*2^x+8=0 ?
The answer to 4^{x+0.5}-17*2^x+8=0 is x=3,x=-1
Solve for x: 4^{x+0.5}-17*2^x+8=0
The solution is x=3,x=-1