What is the answer to 7^x=32 ?

The answer to 7^x=32 is x=(5ln(2))/(ln(7))

The solution is x=(5ln(2))/(ln(7))

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7^x=32

7^{x} = 32

x = \frac{5 ln ( 2 )}{ln ( 7 )}

Decimal Notation

x = 1.78103 \dots

Solution steps

7^{x} = 32

Apply exponent rules

x ln (7) = ln (32)

Solve

x ln (7) = ln (32) : x = \frac{5 ln ( 2 )}{ln ( 7 )}

x = \frac{5 ln ( 2 )}{ln ( 7 )}

7^{x} = 35

3^{x} = 144

a, m^{a + 1} = 0.5

8 \cdot 2^{x} = 4

4^{x + 2} = 8^{2 x}