What is the answer to 2^{2x}-3*2^{2x}+2=0 ?

The answer to 2^{2x}-3*2^{2x}+2=0 is x=0

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2^{2x}-3*2^{2x}+2=0

2^{2 x} - 3 \cdot 2^{2 x} + 2 = 0

x = 0

Solution steps

2^{2 x} - 3 \cdot 2^{2 x} + 2 = 0

Add similar elements:

2^{2 x} - 3 \cdot 2^{2 x} = - 2 \cdot 2^{2 x}

- 2 \cdot 2^{2 x} + 2 = 0

Move

2

to the right side

- 2 \cdot 2^{2 x} = - 2

Divide both sides by

- 2

2^{2 x} = 1

Apply exponent rules

2 x ln (2) = ln (1)

Solve

2 x ln (2) = ln (1) : x = 0

x = 0

9^{6 - x} = 3^{2 x - 4}

2 (e^{x}) + e^{x} = 0

3^{4 x + 1} \cdot 9^{x - 1} = 81

x e^{- x} = - 3 (x e^{- x}) + 1

(6) (8^{x}) = 2 e^{3 x}

What is the answer to 2^{2x}-3*2^{2x}+2=0 ?
The answer to 2^{2x}-3*2^{2x}+2=0 is x=0
Solve for x: 2^{2x}-3*2^{2x}+2=0
The solution is x=0