What is the answer to 2(e^x)+e^x=0 ?

The answer to 2(e^x)+e^x=0 is No Solution for x\in\mathbb{R}

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2(e^x)+e^x=0

2 (e^{x}) + e^{x} = 0

No Solution for x \in R

Solution steps

2 (e^{x}) + e^{x} = 0

Subtract

e^{x}

from both sides

2 e^{x} + e^{x} - e^{x} = 0 - e^{x}

Simplify

2 e^{x} = - e^{x}

Move

e^{x}

to the left side

3 e^{x} = 0

Divide both sides by

3

e^{x} = 0

a^{f (x)}

cannot be zero or negative for

x \in R

No Solution for x \in R

3^{4 x + 1} \cdot 9^{x - 1} = 81

x e^{- x} = - 3 (x e^{- x}) + 1

(6) (8^{x}) = 2 e^{3 x}

A (x) = 500 (1.03)^{x}

4 9^{x + 3} = 7^{x^{2} - 3 x + 8}

What is the answer to 2(e^x)+e^x=0 ?
The answer to 2(e^x)+e^x=0 is No Solution for x\in\mathbb{R}