What is the answer to 2^{x-1}=(4^x)/8 ?

The answer to 2^{x-1}=(4^x)/8 is x=2

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2^{x-1}=(4^x)/8

2^{x - 1} = \frac{4 ^{x}}{8}

x = 2

Solution steps

2^{x - 1} = \frac{4 ^{x}}{8}

Multiply both sides by

8

2^{x - 1} \cdot 8 = \frac{4 ^{x}}{8} \cdot 8

Simplify

2^{x - 1} \cdot 8 = 4^{x}

Apply exponent rules

x + 2 = 2 x

Solve

x + 2 = 2 x : x = 2

x = 2

(- 2)^{x} = - 128

e^{3 x} = \frac{9}{2}

2^{x} - 1 = 100

x, 7 e^{1 x + 2.3} = 136

2^{x} = e^{x + 2}