What is the answer to 2^x-10*2^x+16=0 ?

The answer to 2^x-10*2^x+16=0 is x=(ln(16/9))/(ln(2))

Solve for x: 2^x-10*2^x+16=0

The solution is x=(ln(16/9))/(ln(2))

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2^{x} - 10 \cdot 2^{x} + 16 = 0

x = \frac{ln ( \frac{16}{9} )}{ln ( 2 )}

Solution steps

2^{x} - 10 \cdot 2^{x} + 16 = 0

Add similar elements:

2^{x} - 10 \cdot 2^{x} = - 9 \cdot 2^{x}

- 9 \cdot 2^{x} + 16 = 0

Move

16

to the right side

- 9 \cdot 2^{x} = - 16

Divide both sides by

- 9

2^{x} = \frac{16}{9}

Apply exponent rules

x ln (2) = ln (\frac{16}{9})

Solve

x ln (2) = ln (\frac{16}{9}) : x = \frac{ln ( \frac{16}{9} )}{ln ( 2 )}

x = \frac{ln ( \frac{16}{9} )}{ln ( 2 )}

1 = 2 \cdot e^{- 0.00203 \cdot t}

5 \cdot 2^{2 x} - 3 \cdot 2^{x} - 2 = 0

9 \cdot 8^{x} = 45.68

t, f = p (1 + r)^{t}

n, y^{n} + 9 y = 0

What is the answer to 2^x-10*2^x+16=0 ?
The answer to 2^x-10*2^x+16=0 is x=(ln(16/9))/(ln(2))
Solve for x: 2^x-10*2^x+16=0
The solution is x=(ln(16/9))/(ln(2))