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Popular >

solvefor n,y^n+9y=0

Solution

solve for

n, y^{n} + 9 y = 0

Solution

n = \frac{ln ( - 9 y )}{ln ( y )}

Solution steps

y^{n} + 9 y = 0

Subtract

9 y

from both sides

y^{n} + 9 y - 9 y = 0 - 9 y

Simplify

y^{n} = - 9 y

Apply exponent rules

n ln (y) = ln (- 9 y)

Solve

n ln (y) = ln (- 9 y) : n = \frac{ln ( - 9 y )}{ln ( y )}

n = \frac{ln ( - 9 y )}{ln ( y )}

Popular Examples

3^{2x-6}= 1/(9^{x+1)}

3^{2 x - 6} = \frac{1}{9 ^{x + 1}}

1100=250*2^{1/t}

1100 = 250 \cdot 2^{\frac{1}{t}}

10=200e^{-0.347x}

10 = 200 e^{- 0.347 x}

me^{mx}+3e^{mx}=0

m e^{m x} + 3 e^{m x} = 0

22 = 200 \cdot (0.8)^{t}

Frequently Asked Questions (FAQ)

What is the answer to solvefor n,y^n+9y=0 ?
The answer to solvefor n,y^n+9y=0 is n=(ln(-9y))/(ln(y))