What is the answer to solvefor t,f=p(1+r)^t ?

The answer to solvefor t,f=p(1+r)^t is t=(ln(f/p))/(ln(1+r))

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solvefor t,f=p(1+r)^t

solve for

t, f = p (1 + r)^{t}

t = \frac{ln ( \frac{f}{p} )}{ln ( 1 + r )}

Solution steps

f = p (1 + r)^{t}

Switch sides

p (1 + r)^{t} = f

Divide both sides by

p

(1 + r)^{t} = \frac{f}{p}

Apply exponent rules

t ln (1 + r) = ln (\frac{f}{p})

Solve

t ln (1 + r) = ln (\frac{f}{p}) : t = \frac{ln ( \frac{f}{p} )}{ln ( 1 + r )}

t = \frac{ln ( \frac{f}{p} )}{ln ( 1 + r )}

n, y^{n} + 9 y = 0

3^{2 x - 6} = \frac{1}{9 ^{x + 1}}

1100 = 250 \cdot 2^{\frac{1}{t}}

10 = 200 e^{- 0.347 x}

m e^{m x} + 3 e^{m x} = 0

What is the answer to solvefor t,f=p(1+r)^t ?
The answer to solvefor t,f=p(1+r)^t is t=(ln(f/p))/(ln(1+r))