What is the answer to 2^{2+y}-2^{1+y}=16 ?

The answer to 2^{2+y}-2^{1+y}=16 is y=3

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2^{2+y}-2^{1+y}=16

2^{2 + y} - 2^{1 + y} = 16

y = 3

Solution steps

2^{2 + y} - 2^{1 + y} = 16

Factor

2^{2 + y} - 2^{1 + y} : 2^{1 + y}

2^{1 + y} = 16

Apply exponent rules

1 + y = 4

Solve

1 + y = 4 : y = 3

y = 3

66.1 = 120 - 120 e^{k (0.5)}

0 = 0.9 8^{X}

4^{x + 4} = 5^{x}

8 x = 3. 2^{6 x}

1 0^{x - 1} = 8 \cdot 3^{x}

What is the answer to 2^{2+y}-2^{1+y}=16 ?
The answer to 2^{2+y}-2^{1+y}=16 is y=3
Solve for y: 2^{2+y}-2^{1+y}=16
The solution is y=3