What is the answer to 2^{20x+10}=4^{10x+5} ?

The answer to 2^{20x+10}=4^{10x+5} is True for all x

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2^{20x+10}=4^{10x+5}

2^{20 x + 10} = 4^{10 x + 5}

True for all x

Solution steps

2^{20 x + 10} = 4^{10 x + 5}

Apply exponent rules

20 x + 10 = 2 (10 x + 5)

Solve

20 x + 10 = 2 (10 x + 5) :

True for all

x

True for all x

7^{x + 4} = 8^{x}

\frac{1}{3 e ^{2 - 3 x} + 3} = 7

7^{3 x^{2}} = 4 9^{6 x + 2}

9^{x} - 4 = 3^{x + 1}

e^{x} + 6 \cdot e^{- x} = 5

What is the answer to 2^{20x+10}=4^{10x+5} ?
The answer to 2^{20x+10}=4^{10x+5} is True for all x
Solve for x: 2^{20x+10}=4^{10x+5}
The solution is True for all x