What is the answer to 3^{2x-1}=9sqrt(3) ?

The answer to 3^{2x-1}=9sqrt(3) is x= 7/4

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3^{2x-1}=9sqrt(3)

3^{2 x - 1} = 93

x = \frac{7}{4}

Solution steps

3^{2 x - 1} = 93

Apply exponent rules

2 x - 1 = \frac{5}{2}

Solve

2 x - 1 = \frac{5}{2} : x = \frac{7}{4}

x = \frac{7}{4}

5^{x} = 5^{2}

\frac{1}{2 ^{x + 4}} = 8

2 = 1.0 2^{x}

2 5^{x} \cdot 5^{x^{2}} = 62 5^{2}

2^{4 x} = 256

What is the answer to 3^{2x-1}=9sqrt(3) ?
The answer to 3^{2x-1}=9sqrt(3) is x= 7/4
Solve for x: 3^{2x-1}=9sqrt(3)
The solution is x= 7/4