What is the answer to solvefor x,5(25^x)=3.125^y ?

The answer to solvefor x,5(25^x)=3.125^y is x=(ln(3.125)y-ln(5))/(2ln(5))

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solvefor x,5(25^x)=3.125^y

solve for

x, 5 (2 5^{x}) = 3.12 5^{y}

x = \frac{ln ( 3.125 ) y - ln ( 5 )}{2 ln ( 5 )}

Solution steps

5 (2 5^{x}) = 3.12 5^{y}

Divide both sides by

5

2 5^{x} = \frac{3.12 5 ^{y}}{5}

Apply exponent rules

x ln (25) = ln (\frac{3.12 5 ^{y}}{5})

Solve

x ln (25) = ln (\frac{3.12 5 ^{y}}{5}) : x = \frac{ln ( 3.125 ) y - ln ( 5 )}{2 ln ( 5 )}

x = \frac{ln ( 3.125 ) y - ln ( 5 )}{2 ln ( 5 )}

5^{x + 3} = 7^{4 - 3 x}

2 7^{x - 1} = 9

3^{2 x - 3} \cdot 9 = 1

12 = 21 e^{20 x}

12000 = 1520 \cdot 1.0 4^{x}

What is the answer to solvefor x,5(25^x)=3.125^y ?
The answer to solvefor x,5(25^x)=3.125^y is x=(ln(3.125)y-ln(5))/(2ln(5))