What is the answer to 6^{3x-4}=5^{2x} ?

The answer to 6^{3x-4}=5^{2x} is x=(4ln(6))/(3ln(6)-2ln(5))

Solve for x: 6^{3x-4}=5^{2x}

The solution is x=(4ln(6))/(3ln(6)-2ln(5))

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6^{3 x - 4} = 5^{2 x}

x = \frac{4 ln ( 6 )}{3 ln ( 6 ) - 2 ln ( 5 )}

Decimal Notation

x = 3.32360 \dots

Solution steps

6^{3 x - 4} = 5^{2 x}

Apply exponent rules

(3 x - 4) ln (6) = 2 x ln (5)

Solve

(3 x - 4) ln (6) = 2 x ln (5) : x = \frac{4 ln ( 6 )}{3 ln ( 6 ) - 2 ln ( 5 )}

x = \frac{4 ln ( 6 )}{3 ln ( 6 ) - 2 ln ( 5 )}

1 0^{x} = 17

6 4^{- 15 x - 27} = 8^{3 x^{2} - 3 x}

1 0^{x} = 29

\frac{1}{729} = 3^{x}

- 3^{x} - 9 (3^{- x}) + 10 = 0

What is the answer to 6^{3x-4}=5^{2x} ?
The answer to 6^{3x-4}=5^{2x} is x=(4ln(6))/(3ln(6)-2ln(5))
Solve for x: 6^{3x-4}=5^{2x}
The solution is x=(4ln(6))/(3ln(6)-2ln(5))