What is the answer to 97*0.95^t=35 ?

The answer to 97*0.95^t=35 is t=(ln(35/97))/(ln(0.95))

Solve for t: 97*0.95^t=35

The solution is t=(ln(35/97))/(ln(0.95))

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97 \cdot 0.9 5^{t} = 35

t = \frac{ln ( \frac{35}{97} )}{ln ( 0.95 )}

Solution steps

97 \cdot 0.9 5^{t} = 35

Divide both sides by

97

0.9 5^{t} = \frac{35}{97}

Apply exponent rules

t ln (0.95) = ln (\frac{35}{97})

Solve

t ln (0.95) = ln (\frac{35}{97}) : t = \frac{ln ( \frac{35}{97} )}{ln ( 0.95 )}

t = \frac{ln ( \frac{35}{97} )}{ln ( 0.95 )}

2 \cdot e^{- 6 x} = 95

5^{x^{2}} \cdot 2 5^{x - 1} = 5^{3 x}

4^{2 x} - 6 \cdot 4^{2 x} = - 20

2500 = 2000 (1.04)^{x}

What is the answer to 97*0.95^t=35 ?
The answer to 97*0.95^t=35 is t=(ln(35/97))/(ln(0.95))
Solve for t: 97*0.95^t=35
The solution is t=(ln(35/97))/(ln(0.95))