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Popular >

2*e^{-6x}=95

Solution

2 \cdot e^{- 6 x} = 95

Solution

x = - \frac{ln ( \frac{95}{2} )}{6}

+1

Solution steps

2 e^{- 6 x} = 95

Divide both sides by

2

e^{- 6 x} = \frac{95}{2}

Apply exponent rules

- 6 x = ln (\frac{95}{2})

Solve

- 6 x = ln (\frac{95}{2}) : x = - \frac{ln ( \frac{95}{2} )}{6}

x = - \frac{ln ( \frac{95}{2} )}{6}

Popular Examples

5^{x^2}*25^{x-1}=5^{3x}

5^{x^{2}} \cdot 2 5^{x - 1} = 5^{3 x}

5^{x+3}=\sqrt[4]{25^{x+5}}

4^{2x}-6*4^{2x}=-20

4^{2 x} - 6 \cdot 4^{2 x} = - 20

2500=2000(1.04)^x

2500 = 2000 (1.04)^{x}

log_{10}(3^x)=81

lo g_{10} (3^{x}) = 81

Frequently Asked Questions (FAQ)

What is the answer to 2*e^{-6x}=95 ?
The answer to 2*e^{-6x}=95 is x=-(ln(95/2))/6