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Popular >

solvefor d,c=ba+a^d

Solution

solve for

d, c = ba + a^{d}

Solution

d = \frac{ln ( c - ba )}{ln ( a )}

Solution steps

c = ba + a^{d}

Switch sides

ba + a^{d} = c

Move

ba

to the right side

a^{d} = c - ba

Apply exponent rules

d ln (a) = ln (c - ba)

Solve

d ln (a) = ln (c - ba) : d = \frac{ln ( c - ba )}{ln ( a )}

d = \frac{ln ( c - ba )}{ln ( a )}

Popular Examples

solvefor x,2^{4x-9}=9^{7x-4}solve for

x, 2^{4 x - 9} = 9^{7 x - 4}

log_{10}(100^x)=35

lo g_{10} (10 0^{x}) = 35

3=60(2-60)e^{-0.001x}

3 = 60 (2 - 60) e^{- 0.001 x}

3^{x + 5} = 7

5^x+5^{x+1}+5^{x+2}=155

5^{x} + 5^{x + 1} + 5^{x + 2} = 155

Frequently Asked Questions (FAQ)

What is the answer to solvefor d,c=ba+a^d ?
The answer to solvefor d,c=ba+a^d is d=(ln(c-ba))/(ln(a))