What is the answer to 81^{(x+1)}=9^{(3x-4)} ?

The answer to 81^{(x+1)}=9^{(3x-4)} is x=6

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81^{(x+1)}=9^{(3x-4)}

8 1^{(x + 1)} = 9^{(3 x - 4)}

x = 6

Solution steps

8 1^{(x + 1)} = 9^{(3 x - 4)}

Apply exponent rules

2 (x + 1) = 3 x - 4

Solve

2 (x + 1) = 3 x - 4 : x = 6

x = 6

2^{2 x} + 3 (2^{x}) - 4 = 0

6^{1 - x} = 9

3^{4 x - 7} = 5^{6 x + 11}

5^{2 x} = 8^{x - 1}

e^{2 x} + 7 e^{x} - 8 = 0

What is the answer to 81^{(x+1)}=9^{(3x-4)} ?
The answer to 81^{(x+1)}=9^{(3x-4)} is x=6
Solve for x: 81^{(x+1)}=9^{(3x-4)}
The solution is x=6