What are the solutions to the equation x^2-4x-45=0 ?

The solutions to the equation x^2-4x-45=0 are x=9,x=-5

Find the zeros of x^2-4x-45=0

The zeros of x^2-4x-45=0 are x=9,x=-5

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x^{2} - 4 x - 45 = 0

x = 9, x = - 5

Solution steps

x^{2} - 4 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 45) = 14

x_{1, 2} = \frac{- ( - 4 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 14}{2 \cdot 1}

x = \frac{- ( - 4 ) + 14}{2 \cdot 1} : 9

x = \frac{- ( - 4 ) - 14}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 9, x = - 5

Z < \frac{16 - 16.15}{0.15}

10 n - 7 n - n + 2 n - n = 9

12 x^{2} + 15 x = 16 x + 20

4 x^{2} + 64 = 0

What are the solutions to the equation x^2-4x-45=0 ?
The solutions to the equation x^2-4x-45=0 are x=9,x=-5
Find the zeros of x^2-4x-45=0
The zeros of x^2-4x-45=0 are x=9,x=-5