What are the solutions to the equation 4x^2+64=0 ?

The solutions to the equation 4x^2+64=0 are x=4i,x=-4i

Find the zeros of 4x^2+64=0

The zeros of 4x^2+64=0 are x=4i,x=-4i

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4 x^{2} + 64 = 0

x = 4 i, x = - 4 i

Solution steps

4 x^{2} + 64 = 0

Move

64

to the right side

4 x^{2} = - 64

Divide both sides by

4

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

15 - 3 ∣ x + 4 ∣ > 8

\frac{( \frac{π}{2} )}{4}

256 - 16 t^{2} = 0

3 y + \frac{2}{5} = - \frac{1}{5}

z^{2} = 18 - 7 z

What are the solutions to the equation 4x^2+64=0 ?
The solutions to the equation 4x^2+64=0 are x=4i,x=-4i
Find the zeros of 4x^2+64=0
The zeros of 4x^2+64=0 are x=4i,x=-4i