What is the answer to \sqrt[7]{(2^{(3x-1)})}=32 ?

The answer to \sqrt[7]{(2^{(3x-1)})}=32 is x=12

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\sqrt[7]{(2^{(3x-1)})}=32

x = 12

Solution steps

Apply exponent rules

(3 x - 1) \frac{1}{7} = 5

Solve

(3 x - 1) \frac{1}{7} = 5 : x = 12

x = 12

2^{(\frac{t}{2})} 100 = 40000

2^{x} = - \frac{1}{4}

9^{5 x} = 2 7^{2 x - 4}

2^{x} \cdot 5^{x} = 20

What is the answer to \sqrt[7]{(2^{(3x-1)})}=32 ?
The answer to \sqrt[7]{(2^{(3x-1)})}=32 is x=12
Solve for x: \sqrt[7]{(2^{(3x-1)})}=32
The solution is x=12