What is the answer to 2^{31}=10^x ?

The answer to 2^{31}=10^x is x=(31ln(2))/(ln(10))

Solve for x: 2^{31}=10^x

The solution is x=(31ln(2))/(ln(10))

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2^{31} = 1 0^{x}

x = \frac{31 ln ( 2 )}{ln ( 10 )}

Decimal Notation

x = 9.33192 \dots

Solution steps

2^{31} = 1 0^{x}

Apply exponent rules

31 ln (2) = x ln (10)

Solve

31 ln (2) = x ln (10) : x = \frac{31 ln ( 2 )}{ln ( 10 )}

x = \frac{31 ln ( 2 )}{ln ( 10 )}

6^{x - 1} = 7

3^{(2 x + 1)} = 7^{(x + 1)}

\frac{1}{e ^{- x}} = e^{x}

x 5^{2 x + 3} = \frac{1}{25}

8200 = 6400 \cdot (1.054)^{4 x}

What is the answer to 2^{31}=10^x ?
The answer to 2^{31}=10^x is x=(31ln(2))/(ln(10))
Solve for x: 2^{31}=10^x
The solution is x=(31ln(2))/(ln(10))