What is the answer to 9^{x+10}+22=100 ?

The answer to 9^{x+10}+22=100 is x=(ln(78))/(2ln(3))-10

Solve for x: 9^{x+10}+22=100

The solution is x=(ln(78))/(2ln(3))-10

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9^{x + 10} + 22 = 100

x = \frac{ln ( 78 )}{2 ln ( 3 )} - 10

Decimal Notation

x = - 8.01717 \dots

Solution steps

9^{x + 10} + 22 = 100

Move

22

to the right side

9^{x + 10} = 78

Apply exponent rules

(x + 10) ln (9) = ln (78)

Solve

(x + 10) ln (9) = ln (78) : x = \frac{ln ( 78 )}{2 ln ( 3 )} - 10

x = \frac{ln ( 78 )}{2 ln ( 3 )} - 10

2^{p + 3} = 67

6^{n} - 9 = 0

y, x e^{y} + y e^{x} = 3

4^{x + 1} = 8^{2 x + 3}

(1000) 1.0 5^{3 x} = 3000

What is the answer to 9^{x+10}+22=100 ?
The answer to 9^{x+10}+22=100 is x=(ln(78))/(2ln(3))-10
Solve for x: 9^{x+10}+22=100
The solution is x=(ln(78))/(2ln(3))-10