What is the answer to solvefor x,y-3=4*25^{x+1} ?

The answer to solvefor x,y-3=4*25^{x+1} is x=(ln((y-3)/4))/(2ln(5))-1

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solvefor x,y-3=4*25^{x+1}

solve for

x, y - 3 = 4 \cdot 2 5^{x + 1}

x = \frac{ln ( \frac{y - 3}{4} )}{2 ln ( 5 )} - 1

Solution steps

y - 3 = 4 \cdot 2 5^{x + 1}

Switch sides

4 \cdot 2 5^{x + 1} = y - 3

Divide both sides by

4

2 5^{x + 1} = \frac{y - 3}{4}

Apply exponent rules

(x + 1) ln (25) = ln (\frac{y - 3}{4})

Solve

(x + 1) ln (25) = ln (\frac{y - 3}{4}) : x = \frac{ln ( \frac{y - 3}{4} )}{2 ln ( 5 )} - 1

x = \frac{ln ( \frac{y - 3}{4} )}{2 ln ( 5 )} - 1

\frac{98415}{8} = 8 \cdot 3^{n - 1}

e^{x} = 7.1

e^{x} = 7.9

8^{4 x} = 5^{x - 9}

- 10 \cdot 8^{- 5 n} = - 81

What is the answer to solvefor x,y-3=4*25^{x+1} ?
The answer to solvefor x,y-3=4*25^{x+1} is x=(ln((y-3)/4))/(2ln(5))-1