What is the answer to 2^{x+1}+2^x-2^{x-1}=3^3-7 ?

The answer to 2^{x+1}+2^x-2^{x-1}=3^3-7 is x=3

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2^{x+1}+2^x-2^{x-1}=3^3-7

2^{x + 1} + 2^{x} - 2^{x - 1} = 3^{3} - 7

x = 3

Solution steps

2^{x + 1} + 2^{x} - 2^{x - 1} = 3^{3} - 7

Apply exponent rules

x - 1 = 2

Solve

x - 1 = 2 : x = 3

x = 3

2^{x + 1} = 3 (5^{x})

\frac{1}{e ^{t}} = e^{- t}

x, x^{2} = 2^{x}

0.08 = \frac{20}{2 ^{x}}

10 0^{x} = (\frac{1}{10})^{x - 3}

What is the answer to 2^{x+1}+2^x-2^{x-1}=3^3-7 ?
The answer to 2^{x+1}+2^x-2^{x-1}=3^3-7 is x=3
Solve for x: 2^{x+1}+2^x-2^{x-1}=3^3-7
The solution is x=3