What is the answer to 2000(1.04)^t=1000(1.08)^t ?

The answer to 2000(1.04)^t=1000(1.08)^t is t=(ln(2))/(ln(1.08)-ln(1.04))

Solve for t: 2000(1.04)^t=1000(1.08)^t

The solution is t=(ln(2))/(ln(1.08)-ln(1.04))

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2000 (1.04)^{t} = 1000 (1.08)^{t}

t = \frac{ln ( 2 )}{ln ( 1.08 ) - ln ( 1.04 )}

Decimal Notation

t = 18.36622 \dots

Solution steps

2000 (1.04)^{t} = 1000 (1.08)^{t}

Apply exponent rules

ln (2000) + t ln (1.04) = ln (1000) + t ln (1.08)

Solve

ln (2000) + t ln (1.04) = ln (1000) + t ln (1.08) : t = \frac{ln ( 2 )}{ln ( 1.08 ) - ln ( 1.04 )}

t = \frac{ln ( 2 )}{ln ( 1.08 ) - ln ( 1.04 )}

7^{x} = 0. 5^{x - 1}

\frac{1}{1 0 ^{3}} = 1 0^{x}

x^{2} 2^{x} - 2^{x} 7 = 0

5^{3 - 2 x} = 4 (7^{x})

e^{x} x^{2} = 0

What is the answer to 2000(1.04)^t=1000(1.08)^t ?
The answer to 2000(1.04)^t=1000(1.08)^t is t=(ln(2))/(ln(1.08)-ln(1.04))
Solve for t: 2000(1.04)^t=1000(1.08)^t
The solution is t=(ln(2))/(ln(1.08)-ln(1.04))