What is the answer to 5^x=3^{2x+1} ?

The answer to 5^x=3^{2x+1} is x=(ln(3))/(ln(5)-2ln(3))

Solve for x: 5^x=3^{2x+1}

The solution is x=(ln(3))/(ln(5)-2ln(3))

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5^{x} = 3^{2 x + 1}

x = \frac{ln ( 3 )}{ln ( 5 ) - 2 ln ( 3 )}

Decimal Notation

x = - 1.86906 \dots

Solution steps

5^{x} = 3^{2 x + 1}

Apply exponent rules

x ln (5) = (2 x + 1) ln (3)

Solve

x ln (5) = (2 x + 1) ln (3) : x = \frac{ln ( 3 )}{ln ( 5 ) - 2 ln ( 3 )}

x = \frac{ln ( 3 )}{ln ( 5 ) - 2 ln ( 3 )}

x, 0 = e^{2 x} - 3 e^{x} + 2

7^{2 x + 5} = 5 \cdot (3^{3 x})

2^{x} = \frac{4 ^{x - 2}}{8}

6 e^{1 - x} + 1 = 25

1500000 = 3 (2^{x - 1})

What is the answer to 5^x=3^{2x+1} ?
The answer to 5^x=3^{2x+1} is x=(ln(3))/(ln(5)-2ln(3))
Solve for x: 5^x=3^{2x+1}
The solution is x=(ln(3))/(ln(5)-2ln(3))