What are the solutions to the equation x^3+125=0 ?

The solutions to the equation x^3+125=0 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i

Find the zeros of x^3+125=0

The zeros of x^3+125=0 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i

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x^{3} + 125 = 0

x = - 5, x = \frac{5}{2} - \frac{5 3}{2} i, x = \frac{5}{2} + \frac{5 3}{2} i

Solution steps

x^{3} + 125 = 0

Move

125

to the right side

x^{3} = - 125

For

x^{3} = f (a)

the solutions are

Simplify

x = - 5, x = \frac{5}{2} - \frac{5 3}{2} i, x = \frac{5}{2} + \frac{5 3}{2} i

x^{3} - 6 x^{2} + 12 x - 8 = 0

x^{3} + 5 x^{2} - 4 x - 20 = 0

w^{6} = - 2^{6}

x^{4} - 41 x^{2} + 400 = 0

w^{4} - 18 w^{2} + 81 = 0

What are the solutions to the equation x^3+125=0 ?
The solutions to the equation x^3+125=0 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i
Find the zeros of x^3+125=0
The zeros of x^3+125=0 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i