What are the solutions to the equation x^3+5x^2-4x-20=0 ?

The solutions to the equation x^3+5x^2-4x-20=0 are x=-5,x=-2,x=2

Find the zeros of x^3+5x^2-4x-20=0

The zeros of x^3+5x^2-4x-20=0 are x=-5,x=-2,x=2

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x^{3} + 5 x^{2} - 4 x - 20 = 0

x = - 5, x = - 2, x = 2

Solution steps

x^{3} + 5 x^{2} - 4 x - 20 = 0

Factor

x^{3} + 5 x^{2} - 4 x - 20 : (x + 5) (x + 2) (x - 2)

(x + 5) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 5, x = - 2, x = 2

w^{6} = - 2^{6}

x^{4} - 41 x^{2} + 400 = 0

w^{4} - 18 w^{2} + 81 = 0

9 x^{4} - 24 x^{3} + 16 x^{2} = 0

x^{6} - 26 x^{3} - 27 = 0

What are the solutions to the equation x^3+5x^2-4x-20=0 ?
The solutions to the equation x^3+5x^2-4x-20=0 are x=-5,x=-2,x=2
Find the zeros of x^3+5x^2-4x-20=0
The zeros of x^3+5x^2-4x-20=0 are x=-5,x=-2,x=2