What are the solutions to the equation 0=2x^3-4x^2 ?

The solutions to the equation 0=2x^3-4x^2 are x=0,x=2

Find the zeros of 0=2x^3-4x^2

The zeros of 0=2x^3-4x^2 are x=0,x=2

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0 = 2 x^{3} - 4 x^{2}

x = 0, x = 2

Solution steps

0 = 2 x^{3} - 4 x^{2}

Switch sides

2 x^{3} - 4 x^{2} = 0

Factor

2 x^{3} - 4 x^{2} : 2 x^{2} (x - 2)

2 x^{2} (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 2

x^{3} - 6 x^{2} + 9 x = 0

2 x^{3} + 3 x^{2} - 3 x - 2 = 0

0 = x^{3} - 4 x

5 x^{3} - 5 x^{2} + 6 x - 2 = 0

x^{3} - x^{2} + x - 2 = 4

What are the solutions to the equation 0=2x^3-4x^2 ?
The solutions to the equation 0=2x^3-4x^2 are x=0,x=2
Find the zeros of 0=2x^3-4x^2
The zeros of 0=2x^3-4x^2 are x=0,x=2