What are the solutions to the equation 0=x^3-4x ?

The solutions to the equation 0=x^3-4x are x=0,x=-2,x=2

Find the zeros of 0=x^3-4x

The zeros of 0=x^3-4x are x=0,x=-2,x=2

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0 = x^{3} - 4 x

x = 0, x = - 2, x = 2

Solution steps

0 = x^{3} - 4 x

Switch sides

x^{3} - 4 x = 0

Factor

x^{3} - 4 x : x (x + 2) (x - 2)

x (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 2, x = 2

5 x^{3} - 5 x^{2} + 6 x - 2 = 0

x^{3} - x^{2} + x - 2 = 4

- x^{3} + 12 x + 16 = 0

(x + 5) x^{2} = - (x + 5)

20 = (5 + \frac{0.12 x}{10})^{20}

What are the solutions to the equation 0=x^3-4x ?
The solutions to the equation 0=x^3-4x are x=0,x=-2,x=2
Find the zeros of 0=x^3-4x
The zeros of 0=x^3-4x are x=0,x=-2,x=2