What are the solutions to the equation 2x^3+3x^2-3x-2=0 ?

The solutions to the equation 2x^3+3x^2-3x-2=0 are x=1,x=-1/2 ,x=-2

Find the zeros of 2x^3+3x^2-3x-2=0

The zeros of 2x^3+3x^2-3x-2=0 are x=1,x=-1/2 ,x=-2

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2 x^{3} + 3 x^{2} - 3 x - 2 = 0

x = 1, x = - \frac{1}{2}, x = - 2

Solution steps

2 x^{3} + 3 x^{2} - 3 x - 2 = 0

Factor

2 x^{3} + 3 x^{2} - 3 x - 2 : (x - 1) (2 x + 1) (x + 2)

(x - 1) (2 x + 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 1, x = - \frac{1}{2}, x = - 2

0 = x^{3} - 4 x

5 x^{3} - 5 x^{2} + 6 x - 2 = 0

x^{3} - x^{2} + x - 2 = 4

- x^{3} + 12 x + 16 = 0

(x + 5) x^{2} = - (x + 5)

What are the solutions to the equation 2x^3+3x^2-3x-2=0 ?
The solutions to the equation 2x^3+3x^2-3x-2=0 are x=1,x=-1/2 ,x=-2
Find the zeros of 2x^3+3x^2-3x-2=0
The zeros of 2x^3+3x^2-3x-2=0 are x=1,x=-1/2 ,x=-2