What are the solutions to the equation (x+5)x^2=-(x+5) ?

The solutions to the equation (x+5)x^2=-(x+5) are x=-5,x=i,x=-i

Find the zeros of (x+5)x^2=-(x+5)

The zeros of (x+5)x^2=-(x+5) are x=-5,x=i,x=-i

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(x + 5) x^{2} = - (x + 5)

x = - 5, x = i, x = - i

Solution steps

(x + 5) x^{2} = - (x + 5)

Move

(x + 5)

to the left side

(x + 5) x^{2} + x + 5 = 0

Factor

(x + 5) x^{2} + x + 5 : (x + 5) (x^{2} + 1)

(x + 5) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x^{2} + 1 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = - 5, x = i, x = - i

20 = (5 + \frac{0.12 x}{10})^{20}

x^{3} - 12 x + 16 = 0

x^{3} - 3 x = 0

x^{3} + 2 x^{2} + 3 x + 6 = 0

x^{4} - 10 x^{2} + 29 = 8

What are the solutions to the equation (x+5)x^2=-(x+5) ?
The solutions to the equation (x+5)x^2=-(x+5) are x=-5,x=i,x=-i
Find the zeros of (x+5)x^2=-(x+5)
The zeros of (x+5)x^2=-(x+5) are x=-5,x=i,x=-i