What are the solutions to the equation 20=(5+(0.12x)/(10))^{20} ?

The solutions to the equation 20=(5+(0.12x)/(10))^{20} are x=-319.86780…,x=-513.46552…

Find the zeros of 20=(5+(0.12x)/(10))^{20}

The zeros of 20=(5+(0.12x)/(10))^{20} are x=-319.86780…,x=-513.46552…

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20 = (5 + \frac{0.12 x}{10})^{20}

x = - 319.86780 \dots, x = - 513.46552 \dots

Solution steps

20 = (5 + \frac{0.12 x}{10})^{20}

Switch sides

(5 + \frac{0.12 x}{10})^{20} = 20

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = - 319.86780 \dots, x = - 513.46552 \dots

x^{3} - 12 x + 16 = 0

x^{3} + 2 x^{2} + 3 x + 6 = 0

x^{4} - 10 x^{2} + 29 = 8

x, x^{3} + y^{3} = 1

m^{3} = 64

What are the solutions to the equation 20=(5+(0.12x)/(10))^{20} ?
The solutions to the equation 20=(5+(0.12x)/(10))^{20} are x=-319.86780…,x=-513.46552…
Find the zeros of 20=(5+(0.12x)/(10))^{20}
The zeros of 20=(5+(0.12x)/(10))^{20} are x=-319.86780…,x=-513.46552…